If b^2-4ac=0 and ';a'; cannot =0, then the graph of y=ax^2+bx+c has only one intercept. True or False?

Please explain how you got either answer.If b^2-4ac=0 and ';a'; cannot =0, then the graph of y=ax^2+bx+c has only one intercept. True or False?
The answer is true. If you look at the quadratic formula this portion of it:


b^2 - 4ac is called the discriminant. If a does not equal 0 and the discriminant is positive then the graph has two real x intercepts. If the discriminant is zero then the graph has one real x intercept. If the discriminant is negative then the graph has no real x intercepts.