True or False? If b^2-4ac=0, then the graph of y=ax^2+bx+c has only one x-intercept.?

HEEELP ME!!True or False? If b^2-4ac=0, then the graph of y=ax^2+bx+c has only one x-intercept.?
If b^2 - 4ac = 0, then b^2 = 4ac. Therefore, ac = 4 and b = + or -2.





That means that if b can be multiple things, then there a two y = equations.


y=ax^2+2x+c


y=ax^2-2x+c





so to find the intercept equations:





0=ax^2+2x+c; 0 = x(ax+2)+c; x(ax+2) = -c


0=ax^2-2x+c; 0 = x(ax -2)+c; x(ax-2) = -c


That means x has a positive and a negative value, so there is more than 1 intercept.








False.