[~P v (~P v X)] v (~P v A)For the statement below, if you assume A is known to be true, X is known to be false, and P is not known you c
The statement is true, as follows.
[~P v (~P v X)] v (~P v A). Then substitute:
[~P v (~P v false)] v (~P v true): Then substitute, based on anything OR'd with true is true.
[~P v (~P v false)] v true: Then, once again, substitute, based on anything OR'd with true is true.
true
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