the standard form of a quadratic equation is Ax^2+Bx+C=0
To factorize this B^2-4AC%26gt;=0
in case of this equation
A=1/a
B=1/b
C=1/c
B^2-4AC=1/b^2-4*1/a*1/c=1/b^2-4/ac
B^2-4AC%26gt;=0
so, 1/b^2%26gt;=4/ac
4b^2%26lt;=ac
so 4b^2=ac is trueY=x^2/a+x/b+1/c can be written into a factorized form if 4b^2=ac. Is this true or false?
true
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